5(c+3)=15+2(2c-1)

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Solution for 5(c+3)=15+2(2c-1) equation:


Simplifying
5(c + 3) = 15 + 2(2c + -1)

Reorder the terms:
5(3 + c) = 15 + 2(2c + -1)
(3 * 5 + c * 5) = 15 + 2(2c + -1)
(15 + 5c) = 15 + 2(2c + -1)

Reorder the terms:
15 + 5c = 15 + 2(-1 + 2c)
15 + 5c = 15 + (-1 * 2 + 2c * 2)
15 + 5c = 15 + (-2 + 4c)

Combine like terms: 15 + -2 = 13
15 + 5c = 13 + 4c

Solving
15 + 5c = 13 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
15 + 5c + -4c = 13 + 4c + -4c

Combine like terms: 5c + -4c = 1c
15 + 1c = 13 + 4c + -4c

Combine like terms: 4c + -4c = 0
15 + 1c = 13 + 0
15 + 1c = 13

Add '-15' to each side of the equation.
15 + -15 + 1c = 13 + -15

Combine like terms: 15 + -15 = 0
0 + 1c = 13 + -15
1c = 13 + -15

Combine like terms: 13 + -15 = -2
1c = -2

Divide each side by '1'.
c = -2

Simplifying
c = -2

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