5(c+3)=4(2c-5)

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Solution for 5(c+3)=4(2c-5) equation: 



5(c+3)=4(2c-5)

We move all terms to the left:

5(c+3)-(4(2c-5))=0

We multiply parentheses

5c-(4(2c-5))+15=0



We calculate terms in parentheses: -(4(2c-5)), so:

4(2c-5)

We multiply parentheses

8c-20

Back to the equation:

-(8c-20)



We get rid of parentheses

5c-8c+20+15=0

We add all the numbers together, and all the variables

-3c+35=0

We move all terms containing c to the left, all other terms to the right

-3c=-35

c=-35/-3

c=11+2/3

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