5(c+4)-2c=(c-8)

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Solution for 5(c+4)-2c=(c-8) equation: 



5(c+4)-2c=(c-8)

We move all terms to the left:

5(c+4)-2c-((c-8))=0

We add all the numbers together, and all the variables

-2c+5(c+4)-((c-8))=0

We multiply parentheses

-2c+5c-((c-8))+20=0



We calculate terms in parentheses: -((c-8)), so:

(c-8)

We get rid of parentheses

c-8

Back to the equation:

-(c-8)



We add all the numbers together, and all the variables

3c-(c-8)+20=0

We get rid of parentheses

3c-c+8+20=0

We add all the numbers together, and all the variables

2c+28=0

We move all terms containing c to the left, all other terms to the right

2c=-28

c=-28/2

c=-14

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