5(c+4)-2c=-(c-8)

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Solution for 5(c+4)-2c=-(c-8) equation: 



5(c+4)-2c=-(c-8)

We move all terms to the left:

5(c+4)-2c-(-(c-8))=0

We add all the numbers together, and all the variables

-2c+5(c+4)-(-(c-8))=0

We multiply parentheses

-2c+5c-(-(c-8))+20=0



We calculate terms in parentheses: -(-(c-8)), so:

-(c-8)

We get rid of parentheses

-c+8

We add all the numbers together, and all the variables

-1c+8

Back to the equation:

-(-1c+8)



We add all the numbers together, and all the variables

3c-(-1c+8)+20=0

We get rid of parentheses

3c+1c-8+20=0

We add all the numbers together, and all the variables

4c+12=0

We move all terms containing c to the left, all other terms to the right

4c=-12

c=-12/4

c=-3

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