5(c+4)=5(c-2)

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Solution for 5(c+4)=5(c-2) equation:


Simplifying
5(c + 4) = 5(c + -2)

Reorder the terms:
5(4 + c) = 5(c + -2)
(4 * 5 + c * 5) = 5(c + -2)
(20 + 5c) = 5(c + -2)

Reorder the terms:
20 + 5c = 5(-2 + c)
20 + 5c = (-2 * 5 + c * 5)
20 + 5c = (-10 + 5c)

Add '-5c' to each side of the equation.
20 + 5c + -5c = -10 + 5c + -5c

Combine like terms: 5c + -5c = 0
20 + 0 = -10 + 5c + -5c
20 = -10 + 5c + -5c

Combine like terms: 5c + -5c = 0
20 = -10 + 0
20 = -10

Solving
20 = -10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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