5(c+d)+2(3c+d)=0

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Solution for 5(c+d)+2(3c+d)=0 equation:


Simplifying
5(c + d) + 2(3c + d) = 0
(c * 5 + d * 5) + 2(3c + d) = 0
(5c + 5d) + 2(3c + d) = 0
5c + 5d + (3c * 2 + d * 2) = 0
5c + 5d + (6c + 2d) = 0

Reorder the terms:
5c + 6c + 5d + 2d = 0

Combine like terms: 5c + 6c = 11c
11c + 5d + 2d = 0

Combine like terms: 5d + 2d = 7d
11c + 7d = 0

Solving
11c + 7d = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-7d' to each side of the equation.
11c + 7d + -7d = 0 + -7d

Combine like terms: 7d + -7d = 0
11c + 0 = 0 + -7d
11c = 0 + -7d
Remove the zero:
11c = -7d

Divide each side by '11'.
c = -0.6363636364d

Simplifying
c = -0.6363636364d

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