5(c-1)+2=3(c+1)-2

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Solution for 5(c-1)+2=3(c+1)-2 equation: 



5(c-1)+2=3(c+1)-2

We move all terms to the left:

5(c-1)+2-(3(c+1)-2)=0

We multiply parentheses

5c-(3(c+1)-2)-5+2=0



We calculate terms in parentheses: -(3(c+1)-2), so:

3(c+1)-2

We multiply parentheses

3c+3-2

We add all the numbers together, and all the variables

3c+1

Back to the equation:

-(3c+1)



We add all the numbers together, and all the variables

5c-(3c+1)-3=0

We get rid of parentheses

5c-3c-1-3=0

We add all the numbers together, and all the variables

2c-4=0

We move all terms containing c to the left, all other terms to the right

2c=4

c=4/2

c=2

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