5(c-1)-2(c+3)-2c=8

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Solution for 5(c-1)-2(c+3)-2c=8 equation:


Simplifying
5(c + -1) + -2(c + 3) + -2c = 8

Reorder the terms:
5(-1 + c) + -2(c + 3) + -2c = 8
(-1 * 5 + c * 5) + -2(c + 3) + -2c = 8
(-5 + 5c) + -2(c + 3) + -2c = 8

Reorder the terms:
-5 + 5c + -2(3 + c) + -2c = 8
-5 + 5c + (3 * -2 + c * -2) + -2c = 8
-5 + 5c + (-6 + -2c) + -2c = 8

Reorder the terms:
-5 + -6 + 5c + -2c + -2c = 8

Combine like terms: -5 + -6 = -11
-11 + 5c + -2c + -2c = 8

Combine like terms: 5c + -2c = 3c
-11 + 3c + -2c = 8

Combine like terms: 3c + -2c = 1c
-11 + 1c = 8

Solving
-11 + 1c = 8

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + 1c = 8 + 11

Combine like terms: -11 + 11 = 0
0 + 1c = 8 + 11
1c = 8 + 11

Combine like terms: 8 + 11 = 19
1c = 19

Divide each side by '1'.
c = 19

Simplifying
c = 19

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