5(c-11)=4(c+9)-8c

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Solution for 5(c-11)=4(c+9)-8c equation: 



5(c-11)=4(c+9)-8c

We move all terms to the left:

5(c-11)-(4(c+9)-8c)=0

We multiply parentheses

5c-(4(c+9)-8c)-55=0



We calculate terms in parentheses: -(4(c+9)-8c), so:

4(c+9)-8c

We add all the numbers together, and all the variables

-8c+4(c+9)

We multiply parentheses

-8c+4c+36

We add all the numbers together, and all the variables

-4c+36

Back to the equation:

-(-4c+36)



We get rid of parentheses

5c+4c-36-55=0

We add all the numbers together, and all the variables

9c-91=0

We move all terms containing c to the left, all other terms to the right

9c=91

c=91/9

c=10+1/9

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