5(c-2)+1=3(c-1)

Solution for 5(c-2)+1=3(c-1) equation:

5(c-2)+1=3(c-1)

We move all terms to the left:

5(c-2)+1-(3(c-1))=0

We multiply parentheses

5c-(3(c-1))-10+1=0


We calculate terms in parentheses: -(3(c-1)), so:

3(c-1)

We multiply parentheses

3c-3

Back to the equation:

-(3c-3)


We add all the numbers together, and all the variables

5c-(3c-3)-9=0

We get rid of parentheses

5c-3c+3-9=0

We add all the numbers together, and all the variables

2c-6=0

We move all terms containing c to the left, all other terms to the right

2c=6

c=6/2

c=3