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5(c-2)+2c+12=2
We move all terms to the left:
5(c-2)+2c+12-(2)=0
We add all the numbers together, and all the variables
2c+5(c-2)+10=0
We multiply parentheses
2c+5c-10+10=0
We add all the numbers together, and all the variables
7c=0
c=0/7
c=0
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