5(c-2)+3=2(c+2)+1

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Solution for 5(c-2)+3=2(c+2)+1 equation: 



5(c-2)+3=2(c+2)+1

We move all terms to the left:

5(c-2)+3-(2(c+2)+1)=0

We multiply parentheses

5c-(2(c+2)+1)-10+3=0



We calculate terms in parentheses: -(2(c+2)+1), so:

2(c+2)+1

We multiply parentheses

2c+4+1

We add all the numbers together, and all the variables

2c+5

Back to the equation:

-(2c+5)



We add all the numbers together, and all the variables

5c-(2c+5)-7=0

We get rid of parentheses

5c-2c-5-7=0

We add all the numbers together, and all the variables

3c-12=0

We move all terms containing c to the left, all other terms to the right

3c=12

c=12/3

c=4

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