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5(c-2)-3c=2(c-3)-16
We move all terms to the left:
5(c-2)-3c-(2(c-3)-16)=0
We add all the numbers together, and all the variables
-3c+5(c-2)-(2(c-3)-16)=0
We multiply parentheses
-3c+5c-(2(c-3)-16)-10=0
We calculate terms in parentheses: -(2(c-3)-16), so:We add all the numbers together, and all the variables
2(c-3)-16
We multiply parentheses
2c-6-16
We add all the numbers together, and all the variables
2c-22
Back to the equation:
-(2c-22)
2c-(2c-22)-10=0
We get rid of parentheses
2c-2c+22-10=0
We add all the numbers together, and all the variables
12!=0
There is no solution for this equation
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