5(c-2)=6(5+c)

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Solution for 5(c-2)=6(5+c) equation: 



5(c-2)=6(5+c)

We move all terms to the left:

5(c-2)-(6(5+c))=0

We add all the numbers together, and all the variables

5(c-2)-(6(c+5))=0

We multiply parentheses

5c-(6(c+5))-10=0



We calculate terms in parentheses: -(6(c+5)), so:

6(c+5)

We multiply parentheses

6c+30

Back to the equation:

-(6c+30)



We get rid of parentheses

5c-6c-30-10=0

We add all the numbers together, and all the variables

-1c-40=0

We move all terms containing c to the left, all other terms to the right

-c=40

c=40/-1

c=-40

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