5(c-3)+4=2+c-13

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Solution for 5(c-3)+4=2+c-13 equation: 


Simplifying
5(c + -3) + 4 = 2 + c + -13

Reorder the terms:
5(-3 + c) + 4 = 2 + c + -13
(-3 * 5 + c * 5) + 4 = 2 + c + -13
(-15 + 5c) + 4 = 2 + c + -13

Reorder the terms:
-15 + 4 + 5c = 2 + c + -13

Combine like terms: -15 + 4 = -11
-11 + 5c = 2 + c + -13

Reorder the terms:
-11 + 5c = 2 + -13 + c

Combine like terms: 2 + -13 = -11
-11 + 5c = -11 + c

Add '11' to each side of the equation.
-11 + 11 + 5c = -11 + 11 + c

Combine like terms: -11 + 11 = 0
0 + 5c = -11 + 11 + c
5c = -11 + 11 + c

Combine like terms: -11 + 11 = 0
5c = 0 + c
5c = c

Solving
5c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
5c + -1c = c + -1c

Combine like terms: 5c + -1c = 4c
4c = c + -1c

Combine like terms: c + -1c = 0
4c = 0

Divide each side by '4'.
c = 0

Simplifying
c = 0

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