5(c-3)=2(2c+5)

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Solution for 5(c-3)=2(2c+5) equation: 



5(c-3)=2(2c+5)

We move all terms to the left:

5(c-3)-(2(2c+5))=0

We multiply parentheses

5c-(2(2c+5))-15=0



We calculate terms in parentheses: -(2(2c+5)), so:

2(2c+5)

We multiply parentheses

4c+10

Back to the equation:

-(4c+10)



We get rid of parentheses

5c-4c-10-15=0

We add all the numbers together, and all the variables

c-25=0

We move all terms containing c to the left, all other terms to the right

c=25

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