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5(c-3)=2(2c+5)
We move all terms to the left:
5(c-3)-(2(2c+5))=0
We multiply parentheses
5c-(2(2c+5))-15=0
We calculate terms in parentheses: -(2(2c+5)), so:We get rid of parentheses
2(2c+5)
We multiply parentheses
4c+10
Back to the equation:
-(4c+10)
5c-4c-10-15=0
We add all the numbers together, and all the variables
c-25=0
We move all terms containing c to the left, all other terms to the right
c=25
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