5(c-3)=2c+6

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Solution for 5(c-3)=2c+6 equation: 



5(c-3)=2c+6

We move all terms to the left:

5(c-3)-(2c+6)=0

We multiply parentheses

5c-(2c+6)-15=0

We get rid of parentheses

5c-2c-6-15=0

We add all the numbers together, and all the variables

3c-21=0

We move all terms containing c to the left, all other terms to the right

3c=21

c=21/3

c=7

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