5(c-4)+2c=3(c+10)-2

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Solution for 5(c-4)+2c=3(c+10)-2 equation:


Simplifying
5(c + -4) + 2c = 3(c + 10) + -2

Reorder the terms:
5(-4 + c) + 2c = 3(c + 10) + -2
(-4 * 5 + c * 5) + 2c = 3(c + 10) + -2
(-20 + 5c) + 2c = 3(c + 10) + -2

Combine like terms: 5c + 2c = 7c
-20 + 7c = 3(c + 10) + -2

Reorder the terms:
-20 + 7c = 3(10 + c) + -2
-20 + 7c = (10 * 3 + c * 3) + -2
-20 + 7c = (30 + 3c) + -2

Reorder the terms:
-20 + 7c = 30 + -2 + 3c

Combine like terms: 30 + -2 = 28
-20 + 7c = 28 + 3c

Solving
-20 + 7c = 28 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
-20 + 7c + -3c = 28 + 3c + -3c

Combine like terms: 7c + -3c = 4c
-20 + 4c = 28 + 3c + -3c

Combine like terms: 3c + -3c = 0
-20 + 4c = 28 + 0
-20 + 4c = 28

Add '20' to each side of the equation.
-20 + 20 + 4c = 28 + 20

Combine like terms: -20 + 20 = 0
0 + 4c = 28 + 20
4c = 28 + 20

Combine like terms: 28 + 20 = 48
4c = 48

Divide each side by '4'.
c = 12

Simplifying
c = 12

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