5(c-4)=3(c+6)

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Solution for 5(c-4)=3(c+6) equation: 



5(c-4)=3(c+6)

We move all terms to the left:

5(c-4)-(3(c+6))=0

We multiply parentheses

5c-(3(c+6))-20=0



We calculate terms in parentheses: -(3(c+6)), so:

3(c+6)

We multiply parentheses

3c+18

Back to the equation:

-(3c+18)



We get rid of parentheses

5c-3c-18-20=0

We add all the numbers together, and all the variables

2c-38=0

We move all terms containing c to the left, all other terms to the right

2c=38

c=38/2

c=19

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