5(c-5)+4=2+c-23

Solution for 5(c-5)+4=2+c-23 equation:

Simplifying
5(c + -5) + 4 = 2 + c + -23

Reorder the terms:
5(-5 + c) + 4 = 2 + c + -23
(-5 * 5 + c * 5) + 4 = 2 + c + -23
(-25 + 5c) + 4 = 2 + c + -23

Reorder the terms:
-25 + 4 + 5c = 2 + c + -23

Combine like terms: -25 + 4 = -21
-21 + 5c = 2 + c + -23

Reorder the terms:
-21 + 5c = 2 + -23 + c

Combine like terms: 2 + -23 = -21
-21 + 5c = -21 + c

Add '21' to each side of the equation.
-21 + 21 + 5c = -21 + 21 + c

Combine like terms: -21 + 21 = 0
0 + 5c = -21 + 21 + c
5c = -21 + 21 + c

Combine like terms: -21 + 21 = 0
5c = 0 + c
5c = c

Solving
5c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
5c + -1c = c + -1c

Combine like terms: 5c + -1c = 4c
4c = c + -1c

Combine like terms: c + -1c = 0
4c = 0

Divide each side by '4'.
c = 0

Simplifying
c = 0