5(c-7)=6(c+2)

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Solution for 5(c-7)=6(c+2) equation: 



5(c-7)=6(c+2)

We move all terms to the left:

5(c-7)-(6(c+2))=0

We multiply parentheses

5c-(6(c+2))-35=0



We calculate terms in parentheses: -(6(c+2)), so:

6(c+2)

We multiply parentheses

6c+12

Back to the equation:

-(6c+12)



We get rid of parentheses

5c-6c-12-35=0

We add all the numbers together, and all the variables

-1c-47=0

We move all terms containing c to the left, all other terms to the right

-c=47

c=47/-1

c=-47

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