5(d+1)=4(d-2)

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Solution for 5(d+1)=4(d-2) equation:


Simplifying
5(d + 1) = 4(d + -2)

Reorder the terms:
5(1 + d) = 4(d + -2)
(1 * 5 + d * 5) = 4(d + -2)
(5 + 5d) = 4(d + -2)

Reorder the terms:
5 + 5d = 4(-2 + d)
5 + 5d = (-2 * 4 + d * 4)
5 + 5d = (-8 + 4d)

Solving
5 + 5d = -8 + 4d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-4d' to each side of the equation.
5 + 5d + -4d = -8 + 4d + -4d

Combine like terms: 5d + -4d = 1d
5 + 1d = -8 + 4d + -4d

Combine like terms: 4d + -4d = 0
5 + 1d = -8 + 0
5 + 1d = -8

Add '-5' to each side of the equation.
5 + -5 + 1d = -8 + -5

Combine like terms: 5 + -5 = 0
0 + 1d = -8 + -5
1d = -8 + -5

Combine like terms: -8 + -5 = -13
1d = -13

Divide each side by '1'.
d = -13

Simplifying
d = -13

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