5(d+1)=4(d2)

Solution for 5(d+1)=4(d2) equation:

5(d+1)=4(d2)

We move all terms to the left:

5(d+1)-(4(d2))=0

determiningTheFunctionDomain
5(d+1)-4d2=0

We add all the numbers together, and all the variables

-4d^2+5(d+1)=0

We multiply parentheses

-4d^2+5d+5=0

a = -4; b = 5; c = +5;
Δ = b2-4ac
Δ = 52-4·(-4)·5
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{105}}{2*-4}=\frac{-5-\sqrt{105}}{-8}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{105}}{2*-4}=\frac{-5+\sqrt{105}}{-8}
$