5(d+4)+3=5(d-2)

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Solution for 5(d+4)+3=5(d-2) equation: 



5(d+4)+3=5(d-2)

We move all terms to the left:

5(d+4)+3-(5(d-2))=0

We multiply parentheses

5d-(5(d-2))+20+3=0



We calculate terms in parentheses: -(5(d-2)), so:

5(d-2)

We multiply parentheses

5d-10

Back to the equation:

-(5d-10)



We add all the numbers together, and all the variables

5d-(5d-10)+23=0

We get rid of parentheses

5d-5d+10+23=0

We add all the numbers together, and all the variables

33!=0

There is no solution for this equation

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