5(d+4)=(7d-2)

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Solution for 5(d+4)=(7d-2) equation: 



5(d+4)=(7d-2)

We move all terms to the left:

5(d+4)-((7d-2))=0

We multiply parentheses

5d-((7d-2))+20=0



We calculate terms in parentheses: -((7d-2)), so:

(7d-2)

We get rid of parentheses

7d-2

Back to the equation:

-(7d-2)



We get rid of parentheses

5d-7d+2+20=0

We add all the numbers together, and all the variables

-2d+22=0

We move all terms containing d to the left, all other terms to the right

-2d=-22

d=-22/-2

d=+11

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