5(d+4)=4(d-2)

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Solution for 5(d+4)=4(d-2) equation: 



5(d+4)=4(d-2)

We move all terms to the left:

5(d+4)-(4(d-2))=0

We multiply parentheses

5d-(4(d-2))+20=0



We calculate terms in parentheses: -(4(d-2)), so:

4(d-2)

We multiply parentheses

4d-8

Back to the equation:

-(4d-8)



We get rid of parentheses

5d-4d+8+20=0

We add all the numbers together, and all the variables

d+28=0

We move all terms containing d to the left, all other terms to the right

d=-28

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