5(d-3)+3=2(d+5)-1

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Solution for 5(d-3)+3=2(d+5)-1 equation: 



5(d-3)+3=2(d+5)-1

We move all terms to the left:

5(d-3)+3-(2(d+5)-1)=0

We multiply parentheses

5d-(2(d+5)-1)-15+3=0



We calculate terms in parentheses: -(2(d+5)-1), so:

2(d+5)-1

We multiply parentheses

2d+10-1

We add all the numbers together, and all the variables

2d+9

Back to the equation:

-(2d+9)



We add all the numbers together, and all the variables

5d-(2d+9)-12=0

We get rid of parentheses

5d-2d-9-12=0

We add all the numbers together, and all the variables

3d-21=0

We move all terms containing d to the left, all other terms to the right

3d=21

d=21/3

d=7

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