5(d-4)+2=2(d+2-4)

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Solution for 5(d-4)+2=2(d+2-4) equation: 



5(d-4)+2=2(d+2-4)

We move all terms to the left:

5(d-4)+2-(2(d+2-4))=0

We add all the numbers together, and all the variables

5(d-4)-(2(d-2))+2=0

We multiply parentheses

5d-(2(d-2))-20+2=0



We calculate terms in parentheses: -(2(d-2)), so:

2(d-2)

We multiply parentheses

2d-4

Back to the equation:

-(2d-4)



We add all the numbers together, and all the variables

5d-(2d-4)-18=0

We get rid of parentheses

5d-2d+4-18=0

We add all the numbers together, and all the variables

3d-14=0

We move all terms containing d to the left, all other terms to the right

3d=14

d=14/3

d=4+2/3

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