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5(d-4)+3d-5=3(d+1-2d)+d
We move all terms to the left:
5(d-4)+3d-5-(3(d+1-2d)+d)=0
We add all the numbers together, and all the variables
5(d-4)+3d-(3(-1d+1)+d)-5=0
We add all the numbers together, and all the variables
3d+5(d-4)-(3(-1d+1)+d)-5=0
We multiply parentheses
3d+5d-(3(-1d+1)+d)-20-5=0
We calculate terms in parentheses: -(3(-1d+1)+d), so:We add all the numbers together, and all the variables
3(-1d+1)+d
We add all the numbers together, and all the variables
d+3(-1d+1)
We multiply parentheses
d-3d+3
We add all the numbers together, and all the variables
-2d+3
Back to the equation:
-(-2d+3)
8d-(-2d+3)-25=0
We get rid of parentheses
8d+2d-3-25=0
We add all the numbers together, and all the variables
10d-28=0
We move all terms containing d to the left, all other terms to the right
10d=28
d=28/10
d=2+4/5
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