5(d-4)=-8-d

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Solution for 5(d-4)=-8-d equation: 



5(d-4)=-8-d

We move all terms to the left:

5(d-4)-(-8-d)=0

We add all the numbers together, and all the variables

5(d-4)-(-1d-8)=0

We multiply parentheses

5d-(-1d-8)-20=0

We get rid of parentheses

5d+1d+8-20=0

We add all the numbers together, and all the variables

6d-12=0

We move all terms containing d to the left, all other terms to the right

6d=12

d=12/6

d=2

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