5(d-4)=4d+10

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Solution for 5(d-4)=4d+10 equation: 



5(d-4)=4d+10

We move all terms to the left:

5(d-4)-(4d+10)=0

We multiply parentheses

5d-(4d+10)-20=0

We get rid of parentheses

5d-4d-10-20=0

We add all the numbers together, and all the variables

d-30=0

We move all terms containing d to the left, all other terms to the right

d=30

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