5(d-6)+7=4(d+5)

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Solution for 5(d-6)+7=4(d+5) equation: 



5(d-6)+7=4(d+5)

We move all terms to the left:

5(d-6)+7-(4(d+5))=0

We multiply parentheses

5d-(4(d+5))-30+7=0



We calculate terms in parentheses: -(4(d+5)), so:

4(d+5)

We multiply parentheses

4d+20

Back to the equation:

-(4d+20)



We add all the numbers together, and all the variables

5d-(4d+20)-23=0

We get rid of parentheses

5d-4d-20-23=0

We add all the numbers together, and all the variables

d-43=0

We move all terms containing d to the left, all other terms to the right

d=43

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