5(d-7)=(2d-5)

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Solution for 5(d-7)=(2d-5) equation: 



5(d-7)=(2d-5)

We move all terms to the left:

5(d-7)-((2d-5))=0

We multiply parentheses

5d-((2d-5))-35=0



We calculate terms in parentheses: -((2d-5)), so:

(2d-5)

We get rid of parentheses

2d-5

Back to the equation:

-(2d-5)



We get rid of parentheses

5d-2d+5-35=0

We add all the numbers together, and all the variables

3d-30=0

We move all terms containing d to the left, all other terms to the right

3d=30

d=30/3

d=10

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