5(f+2)=2(2-f)

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Solution for 5(f+2)=2(2-f) equation:


Simplifying
5(f + 2) = 2(2 + -1f)

Reorder the terms:
5(2 + f) = 2(2 + -1f)
(2 * 5 + f * 5) = 2(2 + -1f)
(10 + 5f) = 2(2 + -1f)
10 + 5f = (2 * 2 + -1f * 2)
10 + 5f = (4 + -2f)

Solving
10 + 5f = 4 + -2f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '2f' to each side of the equation.
10 + 5f + 2f = 4 + -2f + 2f

Combine like terms: 5f + 2f = 7f
10 + 7f = 4 + -2f + 2f

Combine like terms: -2f + 2f = 0
10 + 7f = 4 + 0
10 + 7f = 4

Add '-10' to each side of the equation.
10 + -10 + 7f = 4 + -10

Combine like terms: 10 + -10 = 0
0 + 7f = 4 + -10
7f = 4 + -10

Combine like terms: 4 + -10 = -6
7f = -6

Divide each side by '7'.
f = -0.8571428571

Simplifying
f = -0.8571428571

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