5(f+2)=2(3-f)

Solution for 5(f+2)=2(3-f) equation:

Simplifying
5(f + 2) = 2(3 + -1f)

Reorder the terms:
5(2 + f) = 2(3 + -1f)
(2 * 5 + f * 5) = 2(3 + -1f)
(10 + 5f) = 2(3 + -1f)
10 + 5f = (3 * 2 + -1f * 2)
10 + 5f = (6 + -2f)

Solving
10 + 5f = 6 + -2f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '2f' to each side of the equation.
10 + 5f + 2f = 6 + -2f + 2f

Combine like terms: 5f + 2f = 7f
10 + 7f = 6 + -2f + 2f

Combine like terms: -2f + 2f = 0
10 + 7f = 6 + 0
10 + 7f = 6

Add '-10' to each side of the equation.
10 + -10 + 7f = 6 + -10

Combine like terms: 10 + -10 = 0
0 + 7f = 6 + -10
7f = 6 + -10

Combine like terms: 6 + -10 = -4
7f = -4

Divide each side by '7'.
f = -0.5714285714

Simplifying
f = -0.5714285714