5(f+20)=2(3-f)

Solution for 5(f+20)=2(3-f) equation:

Simplifying
5(f + 20) = 2(3 + -1f)

Reorder the terms:
5(20 + f) = 2(3 + -1f)
(20 * 5 + f * 5) = 2(3 + -1f)
(100 + 5f) = 2(3 + -1f)
100 + 5f = (3 * 2 + -1f * 2)
100 + 5f = (6 + -2f)

Solving
100 + 5f = 6 + -2f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '2f' to each side of the equation.
100 + 5f + 2f = 6 + -2f + 2f

Combine like terms: 5f + 2f = 7f
100 + 7f = 6 + -2f + 2f

Combine like terms: -2f + 2f = 0
100 + 7f = 6 + 0
100 + 7f = 6

Add '-100' to each side of the equation.
100 + -100 + 7f = 6 + -100

Combine like terms: 100 + -100 = 0
0 + 7f = 6 + -100
7f = 6 + -100

Combine like terms: 6 + -100 = -94
7f = -94

Divide each side by '7'.
f = -13.42857143

Simplifying
f = -13.42857143