5(f-2)=2(2-f)

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Solution for 5(f-2)=2(2-f) equation:



5(f-2)=2(2-f)
We move all terms to the left:
5(f-2)-(2(2-f))=0
We add all the numbers together, and all the variables
5(f-2)-(2(-1f+2))=0
We multiply parentheses
5f-(2(-1f+2))-10=0
We calculate terms in parentheses: -(2(-1f+2)), so:
2(-1f+2)
We multiply parentheses
-2f+4
Back to the equation:
-(-2f+4)
We get rid of parentheses
5f+2f-4-10=0
We add all the numbers together, and all the variables
7f-14=0
We move all terms containing f to the left, all other terms to the right
7f=14
f=14/7
f=2

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