5(f-4)=2(f+1)

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Solution for 5(f-4)=2(f+1) equation: 



5(f-4)=2(f+1)

We move all terms to the left:

5(f-4)-(2(f+1))=0

We multiply parentheses

5f-(2(f+1))-20=0



We calculate terms in parentheses: -(2(f+1)), so:

2(f+1)

We multiply parentheses

2f+2

Back to the equation:

-(2f+2)



We get rid of parentheses

5f-2f-2-20=0

We add all the numbers together, and all the variables

3f-22=0

We move all terms containing f to the left, all other terms to the right

3f=22

f=22/3

f=7+1/3

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