5(f-4)=3(f+4)

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Solution for 5(f-4)=3(f+4) equation: 



5(f-4)=3(f+4)

We move all terms to the left:

5(f-4)-(3(f+4))=0

We multiply parentheses

5f-(3(f+4))-20=0



We calculate terms in parentheses: -(3(f+4)), so:

3(f+4)

We multiply parentheses

3f+12

Back to the equation:

-(3f+12)



We get rid of parentheses

5f-3f-12-20=0

We add all the numbers together, and all the variables

2f-32=0

We move all terms containing f to the left, all other terms to the right

2f=32

f=32/2

f=16

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