5(f-6)=2(3f)

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Solution for 5(f-6)=2(3f) equation: 



5(f-6)=2(3f)

We move all terms to the left:

5(f-6)-(2(3f))=0

determiningTheFunctionDomain
5(f-6)-23f=0

We add all the numbers together, and all the variables

-23f+5(f-6)=0

We multiply parentheses

-23f+5f-30=0

We add all the numbers together, and all the variables

-18f-30=0

We move all terms containing f to the left, all other terms to the right

-18f=30

f=30/-18

f=-1+2/3

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