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5(g+7)2g=56
We move all terms to the left:
5(g+7)2g-(56)=0
We multiply parentheses
10g^2+70g-56=0
a = 10; b = 70; c = -56;
Δ = b2-4ac
Δ = 702-4·10·(-56)
Δ = 7140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7140}=\sqrt{4*1785}=\sqrt{4}*\sqrt{1785}=2\sqrt{1785}$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-2\sqrt{1785}}{2*10}=\frac{-70-2\sqrt{1785}}{20} $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+2\sqrt{1785}}{2*10}=\frac{-70+2\sqrt{1785}}{20} $
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