5(h+1)=4(2h-1)

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Solution for 5(h+1)=4(2h-1) equation:



5(h+1)=4(2h-1)
We move all terms to the left:
5(h+1)-(4(2h-1))=0
We multiply parentheses
5h-(4(2h-1))+5=0
We calculate terms in parentheses: -(4(2h-1)), so:
4(2h-1)
We multiply parentheses
8h-4
Back to the equation:
-(8h-4)
We get rid of parentheses
5h-8h+4+5=0
We add all the numbers together, and all the variables
-3h+9=0
We move all terms containing h to the left, all other terms to the right
-3h=-9
h=-9/-3
h=+3

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