5(h+1)=6(h-2)

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Solution for 5(h+1)=6(h-2) equation: 



5(h+1)=6(h-2)

We move all terms to the left:

5(h+1)-(6(h-2))=0

We multiply parentheses

5h-(6(h-2))+5=0



We calculate terms in parentheses: -(6(h-2)), so:

6(h-2)

We multiply parentheses

6h-12

Back to the equation:

-(6h-12)



We get rid of parentheses

5h-6h+12+5=0

We add all the numbers together, and all the variables

-1h+17=0

We move all terms containing h to the left, all other terms to the right

-h=-17

h=-17/-1

h=+17

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