5(h+2)=(3h-1)=12

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Solution for 5(h+2)=(3h-1)=12 equation: 



5(h+2)=(3h-1)=12

We move all terms to the left:

5(h+2)-((3h-1))=0

We multiply parentheses

5h-((3h-1))+10=0



We calculate terms in parentheses: -((3h-1)), so:

(3h-1)

We get rid of parentheses

3h-1

Back to the equation:

-(3h-1)



We get rid of parentheses

5h-3h+1+10=0

We add all the numbers together, and all the variables

2h+11=0

We move all terms containing h to the left, all other terms to the right

2h=-11

h=-11/2

h=-5+1/2

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