5(h-1)-2=2(h+3)-1

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Solution for 5(h-1)-2=2(h+3)-1 equation: 



5(h-1)-2=2(h+3)-1

We move all terms to the left:

5(h-1)-2-(2(h+3)-1)=0

We multiply parentheses

5h-(2(h+3)-1)-5-2=0



We calculate terms in parentheses: -(2(h+3)-1), so:

2(h+3)-1

We multiply parentheses

2h+6-1

We add all the numbers together, and all the variables

2h+5

Back to the equation:

-(2h+5)



We add all the numbers together, and all the variables

5h-(2h+5)-7=0

We get rid of parentheses

5h-2h-5-7=0

We add all the numbers together, and all the variables

3h-12=0

We move all terms containing h to the left, all other terms to the right

3h=12

h=12/3

h=4

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