5(h-4)=-2(3-2h)

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Solution for 5(h-4)=-2(3-2h) equation: 



5(h-4)=-2(3-2h)

We move all terms to the left:

5(h-4)-(-2(3-2h))=0

We add all the numbers together, and all the variables

5(h-4)-(-2(-2h+3))=0

We multiply parentheses

5h-(-2(-2h+3))-20=0



We calculate terms in parentheses: -(-2(-2h+3)), so:

-2(-2h+3)

We multiply parentheses

4h-6

Back to the equation:

-(4h-6)



We get rid of parentheses

5h-4h+6-20=0

We add all the numbers together, and all the variables

h-14=0

We move all terms containing h to the left, all other terms to the right

h=14

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