5(i+2)=(i-1)

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Solution for 5(i+2)=(i-1) equation:



5(i+2)=(i-1)
We move all terms to the left:
5(i+2)-((i-1))=0
We multiply parentheses
5i-((i-1))+10=0
We calculate terms in parentheses: -((i-1)), so:
(i-1)
We get rid of parentheses
i-1
Back to the equation:
-(i-1)
We get rid of parentheses
5i-i+1+10=0
We add all the numbers together, and all the variables
4i+11=0
We move all terms containing i to the left, all other terms to the right
4i=-11
i=-11/4
i=-2+3/4

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