5(i+2)=2(r-4)-6

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Solution for 5(i+2)=2(r-4)-6 equation:


Simplifying
5(i + 2) = 2(r + -4) + -6

Reorder the terms:
5(2 + i) = 2(r + -4) + -6
(2 * 5 + i * 5) = 2(r + -4) + -6
(10 + 5i) = 2(r + -4) + -6

Reorder the terms:
10 + 5i = 2(-4 + r) + -6
10 + 5i = (-4 * 2 + r * 2) + -6
10 + 5i = (-8 + 2r) + -6

Reorder the terms:
10 + 5i = -8 + -6 + 2r

Combine like terms: -8 + -6 = -14
10 + 5i = -14 + 2r

Solving
10 + 5i = -14 + 2r

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 5i = -14 + -10 + 2r

Combine like terms: 10 + -10 = 0
0 + 5i = -14 + -10 + 2r
5i = -14 + -10 + 2r

Combine like terms: -14 + -10 = -24
5i = -24 + 2r

Divide each side by '5'.
i = -4.8 + 0.4r

Simplifying
i = -4.8 + 0.4r

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