5(i+2)=8(-i)

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Solution for 5(i+2)=8(-i) equation: 



5(i+2)=8(-i)

We move all terms to the left:

5(i+2)-(8(-i))=0

We add all the numbers together, and all the variables

5(i+2)-(8(-1i))=0

We multiply parentheses

5i-(8(-1i))+10=0



We calculate terms in parentheses: -(8(-1i)), so:

8(-1i)

We multiply parentheses

-8i

Back to the equation:

-(-8i)



We get rid of parentheses

5i+8i+10=0

We add all the numbers together, and all the variables

13i+10=0

We move all terms containing i to the left, all other terms to the right

13i=-10

i=-10/13

i=-10/13

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