5(i+2)=8(I-1)

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Solution for 5(i+2)=8(I-1) equation:


5(i+2)=8(i-1)

We simplify the equation to the form, which is simple to understand
5(i+2)=8(i-1)

Reorder the terms in parentheses
+(+5i+10)=8*(i-1)

Remove unnecessary parentheses
+5i+10=+8+*(+i-1+)

Reorder the terms in parentheses
+5i+10=+(+8i-8)

Remove unnecessary parentheses
+5i+10=+8i-8

We move all terms containing i to the left and all other terms to the right.
+5i-8i=-8-10

We simplify left and right side of the equation.
-3i=-18

We divide both sides of the equation by -3 to get i.
i=6

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